Tuesday 26 July 2022

Date Functions in sql

Find Age in days:

SQL> select to_date(sysdate) - to_date ( '07-Nov-2013') Age_in_days from dual;

AGE_IN_DAYS

-----------

       3183


Age in Months:   

SQL> select MONTHS_BETWEEN (sysdate,'07-Nov-2013') Age_in_Months from dual;

AGE_IN_MONTHS

-------------

   104.619876


Age in Years:

SQL> select MONTHS_BETWEEN (sysdate,'07-Nov-2013') /12 Age_in_Year from dual;

AGE_IN_YEAR

-----------

 8.71832353


Day from date:

SQL> select  TO_CHAR( sysdate, 'DAY' ) from dual;

TO_CHAR(SYSDATE,'DAY')

------------------------------------

TUESDAY



Date format:

SQL> select  TO_CHAR( sysdate, 'DL' ) from dual;

TO_CHAR(SYSDATE,'DL')

-----------------------------------------------------------------------------------

Tuesday, July 26, 2022


Day of week (1-7):

SQL> select  TO_CHAR( sysdate, 'D' ) from dual; 

T

-

3


Name of day:

SQL> select  TO_CHAR( sysdate, 'DAY' ) from dual; 


TO_CHAR(SYSDATE,'DAY')

------------------------------------

TUESDAY


Name of Day:

SQL> select  TO_CHAR( sysdate, 'DY' ) from dual;

TO_CHAR(SYSD

------------

TUE


Day of month (1-31):

SQL> select  TO_CHAR( sysdate, 'DD' ) from dual;

TO

--

26


SQL> select to_char(sysdate,'DDth') day from dual;

DAY

----

26TH



SQL> select to_char(sysdate,'Ddspth') from dual;

TO_CHAR(SYSDAT

--------------

Twenty-Sixth



Day of year (1-366):

SQL> select  TO_CHAR( sysdate, 'DDD' ) from dual;

TO_

---

207


Year format:

SQL> select  TO_CHAR( sysdate, 'YEAR') from dual;  


TO_CHAR(SYSDATE,'YEAR')

------------------------------------------

TWENTY TWENTY-TWO


SQL> select  TO_CHAR( sysdate, 'YYYY') year from dual;

YEAR

----

2022


SQL> select  TO_CHAR( sysdate, 'YYY') year from dual;

yea

---

022


SQL> select  TO_CHAR( sysdate, 'YY') year from dual;

ye

--

22


SQL> select  TO_CHAR( sysdate, 'Y')  year  from dual;

y

-

2



Month Format:

SQL> select  TO_CHAR( sysdate, 'MONTH') from dual;

TO_CHAR(SYSDATE,'MONTH')

------------------------------------

JULY


SQL> select  TO_CHAR( sysdate, 'MON') from dual;

TO_CHAR(SYSD

------------

JUL


SQL> select  TO_CHAR( sysdate, 'MM') from dual;

TO

--

07



Few more formats based on date: 

SQL> select to_char(sysdate,'DDth Month ') from dual;

TO_CHAR(SYSDATE,'DDTHMONTH')

------------------------------------------

26TH July



SQL> select to_char(sysdate,'DDth Month Day') from dual;

TO_CHAR(SYSDATE,'DDTHMONTHDAY')

-----------------------------------------------------------

26TH July      Tuesday



SQL> select to_char(sysdate,'DDth Month Day Year') from dual;

TO_CHAR(SYSDATE,'DDTHMONTHDAYYEAR')

-----------------------------------------------------------

26TH July      Tuesday   Twenty Twenty-Two



SQL> select to_char(sysdate,'Day DDth Month YYYY') from dual;

TO_CHAR(SYSDATE,'DAYDDTHMONTHYYYY')

-----------------------------------------------------

Tuesday   26TH July      2022


SQL> select to_char(sysdate,'YYYY Month DDth') from dual;


TO_CHAR(SYSDATE,'YYYYMONTHDDTH')

----------------------------------------------

2022 July      26TH



next_day:

Find next Saturday or any day:

SQL> select next_day(sysdate,'SATURDAY') Next_Saturday from dual;

NEXT_SATURDAY

--------------------

30-Jul-2022


SQL> select next_day('07-Nov-2013','THURSDAY') from dual;

NEXT_DAY('07-NOV-201

--------------------

14-Nov-2013


First Monday of Current Month:

SQL>  select next_day(trunc(sysdate, 'mm'), 'monday') first_monday    from dual;

FIRST_MONDAY

--------------------

04-Jul-2022


First Monday of Previous Month:

SQL> select next_day(add_months(trunc(sysdate, 'mm'), -1), 'monday') first_monday    from dual;

FIRST_MONDAY

--------------------

06-Jun-2022


First Monday of Next Month:

SQL> select next_day(add_months(trunc(sysdate, 'mm'), +1), 'monday') first_monday    from dual;


FIRST_MONDAY

--------------------

08-Aug-2022


first week day of current month:

SQL> select  TO_CHAR(trunc(sysdate, 'mm'),'DAY') first_day_ofMonth    from dual;

FIRST_DAY_OFMONTH

------------------------------------

FRIDAY


Find First day of month for next n months:

SQL>  select  TO_CHAR(add_months(trunc(sysdate, 'mm'), level-1),'MON YYYY') Month_Year,TO_CHAR(add_months(trunc(sysdate, 'mm'), level-1),'DAY') First_day_of_Month from  dual  connect by level <= 12;

MONTH_YEAR        FIRST_DAY_OF_MONTH

----------------- ------------------------------------

JUL 2022          FRIDAY

AUG 2022          MONDAY

SEP 2022          THURSDAY

OCT 2022          SATURDAY

NOV 2022          TUESDAY

DEC 2022          THURSDAY

JAN 2023          SUNDAY

FEB 2023          WEDNESDAY

MAR 2023          WEDNESDAY

APR 2023          SATURDAY

MAY 2023          MONDAY

JUN 2023          THURSDAY

12 rows selected.


Date format at session level:

alter session set nls_date_format = 'DD-Mon-YYYY';

alter session set nls_timestamp_format = 'DD-Mon-YYYY hh24:mi:ss';




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